14x^2-36x-72=0

Solution for 14x^2-36x-72=0 equation:

14x^2-36x-72=0

a = 14; b = -36; c = -72;
Δ = b2-4ac
Δ = -362-4·14·(-72)
Δ = 5328
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5328}=\sqrt{144*37}=\sqrt{144}*\sqrt{37}=12\sqrt{37}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-12\sqrt{37}}{2*14}=\frac{36-12\sqrt{37}}{28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+12\sqrt{37}}{2*14}=\frac{36+12\sqrt{37}}{28}
$